Having coached, mentored and tutored hundreds -- if not thousands of candidates in the last decade and half, Im happy to provide DAILY practice for the CSET. To be clear, these Qs reflect the difficulty of those on the test but the style may (deliberately) differ; the content = subject-matter knowledge you need to succeed is absolutely FAIR GAME. 1. SUBTEST 1: For , which of the following statements are FALSE? [There may be more than 1 answer. For better comprehension, CORRECT the statements that are incorrect.] a) The Increasing Interval is . b) The Domain is . c) The V.A. is d) The H.A. is . 2. SUBTEST 2. Given the function , write the equation of a new function, AFTER is translated 3 units LEFT and 4 units UP. Answers shall be posted the FOLLOWING day Jay. https://csetmathguru.weebly.com/

Off top of my head, 1. C is false, x = 4 is the VA. Logs aren't even defined for less than 0. B is true. D is false, natural log functions do not converge. A is false, the increasing interval is the domain itself. 2. -4 sqrt(x - 1) + 3 Passed these stupid tests a while back.

The answer to #1 is since the original function was shifted 2 units LEFT from the parent function, so 3 units FURTHER left would make x = -5 the relevant ordinate.

#3. SUBTEST 1. If a root of , which of the following are also roots of ? Choose ALL that apply. #4. SUBTEST 1. The graph of a polynomial function is given below: Which of the following could be the polynomial function (of lowest degree)? Jay. https://csetmathguru.weebly.com/

#7. SUBTEST 2. A soft drink dispenser can be adjusted to deliver any fixed number of ounces of soft drink. If the machine is operating with a standard deviation in delivery equal to 0.3 oz, what should the mean setting be so that a 12 oz cup will overflow less than 1% of the time? 11.23 oz 11.3 oz 11.7 oz. 12.7 oz 12.77 oz Jay. https://csetmathguru.weebly.com/

Solution to #3. Since x = -4 is a root, then x + 4 is a factor. By long division or synthetic division, divide the given polynomial by (x + 4)...and factor the left-over "reduced" quadratic factor to get f(x) = . Solution to #4. At x = 3, f(x) "touches" the x-axis, so the exponent of (x - 3) must be EVEN [2 ~ lowest degree] whereas at x = -3, f(x) "crosses" the x-axis, so the exponent of (x + 3) must be ODD [1 ~ lowest degree] BUT the "squiggle" at x = -3 indicates that the power MUST be 3 or greater...therefore 3 ~ lowest degree! The answer is choice #2 since the 1st one has a negative leading-term which isnt suggested by the graph... Jay. https://csetmathguru.weebly.com/